x^2+((19/4)x)-(5/4)=0

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Solution for x^2+((19/4)x)-(5/4)=0 equation: 



x^2+((19/4)x)-(5/4)=0



Domain of the equation: 4)x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

x^2+((+19/4)x)-(+5/4)=0

We get rid of parentheses

x^2+((+19/4)x)-5/4=0

We calculate fractions


x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$

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